Question

find the equation of straight line passing through the points ,(-3,2) and (6,11)​

Answer 1

Given :

• (-3, 2)
• (6, 11)

To Find :

The equation of straight line passing through the points.

Solution :

We will have to solve it by the concept of two point form of a line.

Two point form of a line is given by,

$\boxed{\bf y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}$

where,

• x₁ = -3
• x₂ = 6
• y₁ = 2
• y₂ = 11

Substituting the values,

$\\ :\implies\sf y-2=\dfrac{11-2}{6-(-3)}(x-(-3))$

$\\ :\implies\sf y-2=\dfrac{9}{6+3}(x+3)$

$\\ :\implies\sf y-2=\dfrac{9}{9}(x+3)$

$\\ :\implies\sf y-2=\dfrac{\not{9}}{\not{9}}(x+3)$

$\\ :\implies\sf y-2=1(x+3)$

$\\ :\implies\sf y-2=x+3$

$\\ :\implies\sf y=x+3+2$

$\\ :\implies\sf y=x+5$

$\\ :\implies\sf 0=x-y+5$

$\\ :\implies\sf x-y+5=0$

$\\ \therefore\boxed{\bf x-y+5=0.}$

The equation of the line is x - y + 5 = 0.