Question

Find the equation of straight line passing through the
point (-1, 1) and making an angle
with positive direction of x-axis.​

Answer 1

Answer:

The equation for the lines is:

Step-by-step explanation:

y-y1 = m(x-x1) where m is the slope

Let us substitute with (-2,3)

==> y- 3 = m(x+2)

Since the line makes a 60 degree angle , then

the slope = y2-y1/x2-x1 = tan60 = sqrt3

==> y- 3 = (sqrt3)(x+2)

==> y-3 = sqrt3)*x + 2sqrt3

==> y= (sqrt3)*x + (3+sqrt3)