Find the equation of straight line passing through the point (4,5) and equally inclided to the line
Answers
Answered by
0
hey here is your answer
the straight line which passes through
P(4;5)P(4;5)
has the equation
y=m(x−4)+5y=m(x−4)+5
converting the others into the Hessian Normalform we get
0=4y−3x+7±50=4y−3x+7±5
and the other
0=5y−12x−6±130=5y−12x−6±13
the
Point(0;−4m+5)Point(0;−4m+5)
is situated on our line and we must compute
|5(−4m+5)−6|13=|4(−3m+5)+7|5|5(−4m+5)−6|13=|4(−3m+5)+7|5
fromk here you will get m
make it brainliest
the straight line which passes through
P(4;5)P(4;5)
has the equation
y=m(x−4)+5y=m(x−4)+5
converting the others into the Hessian Normalform we get
0=4y−3x+7±50=4y−3x+7±5
and the other
0=5y−12x−6±130=5y−12x−6±13
the
Point(0;−4m+5)Point(0;−4m+5)
is situated on our line and we must compute
|5(−4m+5)−6|13=|4(−3m+5)+7|5|5(−4m+5)−6|13=|4(−3m+5)+7|5
fromk here you will get m
make it brainliest
Similar questions