Question

Find the equation of straight line passing through the two points (1,2) and (4,3​

Answer 1

see the attachment.........

Answer 2

The correct answer is "x-3y+5 = 0". Further explanation is given below.

Step-by-step explanation:

Given points are:

(1,2) = (x1,y1)

(4,3) = (x2,y2)

As we know, Equation of line is:

(y-y1) = $\frac{y2-y1}{x2-x1}$ (x-x1)

On putting the values in the above formula, we get

⇒  (y-2) = $\frac{3-2}{4-1}$ (x-1)

⇒  (y-2) = $\frac{1}{3}$ (x-1)

 3(y-2) = 1(x-1)

⇒  3y-6 = x-1

On adding "1" both sides, we get

⇒  3y-6+1 = x-1+1

⇒  3y-5 = x

⇒  x-3y+5 = 0

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