Question

find the equation of straight line through the interesting of line 7 x + 3 Y is equal to 10 5 x minus 4 x square is equal to 1 and parallel to the line 13x+5y+12=0​

Answer 1

Answer:

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Step-by-step explanation:

Solution :

First, let us find the point of intersection of the given lines 7x + 3y = 10, 5x − 4y = 1.

7x + 3y = 10 ----(1)

5x − 4y = 1 ----(2)

4(1) + 3(2)

28x + 12y = 40

15x - 12y = 3

------------------

43x = 43

x = 1

By applying the value of x in (1), we get

7(1) + 3y = 10

7 + 3y = 10

3y = 10 - 7

3y = 3

y = 1

So, the point of intersection of the given lines is (1, 1)

The required line is passing through the point (1, 1) and parallel to the line 13x + 5y + 12 = 0

Slope of the required line = -13/5

(y - y1) = m(x - x1)

(y - 1) = (-13/5)(x - 1)

5(y - 1) = -13(x - 1)

5y - 5 = -13x + 13

13x + 5y - 5 - 13 = 0

13x + 5y - 18 = 0