Find the equation of straight line through the point (2,3) whose intercept on x-axis is twice that on y-axis.
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Consider a line through (x1,y1)=(0,c) and (x2,y2)=(2c,0). The slope of the line is given by the formula:
m=y2−y1x2−x1=0−c2c−0=−c2c=−12
A line through a point (x0,y0) with slope m can be described in point slope form as:
y−y0=m(x−x0)
So in our example, with (x0,y0)=(2,3) and m=−12 we have:
y−3=−12(x−2) point slope form
Multiplying out the right hand side, this becomes:
y−3=−1
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