Question

find the equation of straight line which passes through the point (2,3) and whose slope is 3​

Answer 1

Answer:

m(slope)=3

y-3=3(x-2)

y-3=3x-6

3x-y-6+3=0

3x-y-3=0(answer)

Step-by-step explanation:

m=slope

equation of line=y-y1=m(x-x1)

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Answer 2

Answer:

given point (2,3)

given slope m=3

then the formula is (y-y1)=m(x-x1)

where X1=2

y1=3

now substitute the values in above equation

y-3=3(x-2)

by solving this we will get

3x-y-3=0

which is the required equation passing through (2,3) point with the slope 3