Question

find the equation of straight lines passimg through points P(3,3) and Q(7,6).find the intercept of the line and the length of the portion of the line intercepted between axes

Answer 1

Answer:

please check the answer

Answer 2

Answer:

line eqn     3x-4y-3=0

intercept    b=3/4=0.75

length=5/4

Step-by-step explanation:

P(x1,y1)=(3,3)   Q(x2,y2)=(7,6)

line eqn:                                            intercept of line:

y-y1=m(x-x1)        m=(3-6)/(3-7)        b=y-mx at (P or Q)

y-3=(3/4)(x-3)         =3/4                      =3-(3/4)3 at P

4y-12=3x-9                                           =(12-9)/4=3/4                        

3x-4y-3=0

x-intercept y=0            y-intercept x=0        length=root((0-1)^2 + (-3/4)^2)

3x=3                              y= - 3/4                                =root(25/16)                  

x=1   (1,0)                       (0,- 3/4)                              =5/4