Question

Find the equation of straight lines passing through (1, 2) and making an angle of 60º
with the line 3 2 0 x y    .

Answer 1

Answer:

Solution

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3

x+y=1

slope of line =−

b

a

=−

1

3

=−

3

Angle between two line i.e. tanθ=

∣

∣

∣

∣

∣

1+m

1

m

2

m

1

−m

2

∣

∣

∣

∣

∣

Let slope of line that passes through (3,−2) be m

tan60

∘

=

∣

∣

∣

∣

∣

∣

1+m(−

3

)

m−(−

3

)

∣

∣

∣

∣

∣

∣

3

=

∣

∣

∣

∣

∣

∣

1−

3

m

m+

3

∣

∣

∣

∣

∣

∣

1−

3

m

m+

3

=±

3

1−

3

m

m+

3

=

3

m+

3

=

3

−3m

⇒m=0

1−

3

m

m+

3

=−

3

m+

3

=−

3

+3m

−2m=−2

3

⇒m=

3

Equtaion of line with slope m=0

y+2=0(x−3)

y+2=0

Equation of line with slope m=

3

y+2=

3

(x−3)

y−

3

x+2+3

3

=0

Step-by-step explanation:

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