Question

Find the equation of tangent and normal to the circle ^2+ ^2-3+10y-5=0 at (4,-1)

Answer 1

Step-by-step explanation: Since the tangent is perpendicular to the radius  

of the circle at the point (1,2) the normal, which is  

⊥ lag to the tangent must be ∥ el to the radius  

So we need gradient, since we have given fixed point  

(1,2) with center (0,0)  

gradient (slope of the normal is ) =  

2−0

1−0

​

=  

2

1

​

 

equation of normal ⇒y−y  

1

​

=m(x−x  

1

​

)

(y−1)=  

2

1

​

(x−2)

2y−2=x−2

2y=x

y=  

2

1

​

x