Question

Find the equation of tangent at point where the curve y=2e^(-x/3) cuts Y-axis?

Answer 1

Step-by-step explanation:

This is the general rule when dealing with the irrational number

e

If

y

=

e

f

(

x

)

, then

y

'

=

f

'

(

x

)

e

f

(

x

)

So, the differential is

y

'

=

−

2

3

e

−

x

3

To find an equation of a tangent at a point on this graph, we would need a point, which is not given in the question