Question

Find the equation of tangent of circle x²+y²-6x+2y + 1=0 on exterior point (3,-1)

Do answer the question only if you know the correct answer and complete solution! ​

Answer 1

Step-by-step explanation:

Equation of tangent for circle ⭕ =

replace

x^2 by xx1

y^2 by yy1

x by (x+x1)/2

y by (y+y1)/2

here x1=3

y1 = -1

Now apply this to the given equation of circle.

But what is different here

the given point is not an external point as it is the centre of the circle ⭕.

Hence No tangent can be drawn from the given point.