Question

Find the equation of tangent of the given function y=sin^2x at x=(0, 1)
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Answer 1

Answer:

Given: curve: y=sinx

Given: curve: y=sinxTo find: Eq of tangent drawn to curve at (0,0)

Given: curve: y=sinxTo find: Eq of tangent drawn to curve at (0,0)solution: y=sinx

$\frac{dy}{dx} = \cos(x)$

$\frac{dy}{dx} \frac{}{(0.0)} \cos(0) = 1$

Equation of tangent at (0,0) y−0=1(x−0)

Equation of tangent at (0,0) y−0=1(x−0)⇒y=x

Equation of tangent at (0,0) y−0=1(x−0)⇒y=x∴y=x is required equation.