Question

Find the equation of tangent to curve y =x2 - 4x + 2 at point 4,2

Answer 1

Answer:

We first need to find the gradient of the tangent at x=4:

f'(x)= dy/dx = 2x-4

f'(4)=m= 4

Using point-gradient form should help us get the equation of the tangent:

$(y-y_1)=m(x-x_1)$ where (x₁,y₁) is one of the points along the tangent and m is the gradient of the tangent.

(y-2)=4(x-4)

y-2=4x-16

y=4x-14

Hence solved.

Hope that helps :)

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

We first need to find the gradient of the tangent at x=4:

f'(x)= dy/dx = 2x-4

f'(4)=m= 4

Using point-gradient form should help us get the equation of the tangent:

where (x₁,y₁) is one of the points along the tangent and m is the gradient of the tangent.

(y-2)=4(x-4)

y-2=4x-16

y=4x-14

Hence solved.

Hope that helps :)