Question

Find the equation of tangent to the curve given by x=asin^2t y=bcos^2t when t=pi/2

Answer 1

Answer:

ax+by-a^2=0

Step-by-step explanation:

x=asin^2 t

dx/dt= a(2sin t)(cos t)

= 2asin t cos t

= a sin2t

y=bcos^2 t

dy/dt= b(2cos t)(-sin t)

= -2bsin t cos t

= -b sin2t

dy/dx= slope

= -b sin2t

a sint2t

= -b

a

equation of tangent

y2-y1=m(x2-x1)

y2=y y1=0 x2=x x1=a

y-0=-b(x-a)

a

aY=-bx+ba

bx+ay-ba=0