Question

Find the equation of tangent to the curve y=x-7/(x-2)(x-3)
at the point,where it cuts the X-aris.​

Answer 1

Step-by-step explanation:

y=x-7/(x-2)(x-3) that is x-7/ X Square - 6 ( cancel the square with normal X)

-7/x-6 x= - 7 × - 6 = 42