Question

Find the equation of the chord of the circle x^2+y^2=81 which is bisected at the point (-2,3)

Answer 1

The chord of the circle will be that line perpendicular to the diameter of the circle , intersecting at the given point.

By finding the center of the circle, we can find the slope of the diameter of the circle passing through the given point.  Then, we can find the slope of the chord, as the product of perpendicular lines is -1.

now using the one point and the slope formula for the straight lines, get the equation of the line