Question

find the equation of the Ciecle where
diameter is the Common Chord of
Circle s-x² + y² + 2x +3y + 1 =0
s = x² + y² + 4x + 3y +2=0​

Answer 1

Answer:

The equation of the circle whose diameter is the common chord of the circles; x2+y2+3x+2y+1=0 & x2+y2+3x+4y+2=0 is: x2+y2+8x+10y+2=0 x2+y2-5x+4y+7=0 2x2+2y2+6x+2y+1=0 None of these.

Answer 2

Common chord of given circles is S

1

−S

2

=0

∴6y+6=0

y=−1 is comman chord.

Now, we have to calculate a length of common chord of given circles.

Equation of AB is y+1=0

∴AE=

∣

∣

∣

∣

∣

∣

∣

∣

1

2

3

+1

∣

∣

∣

∣

∣

∣

∣

∣

=

2

5

∴AE=

4

29

−

4

25

=1

So, length of chord 2.

So, the equation of the circle is

⇒(x+1)

2

+(y+1)

2

=1

⇒x

2

+y

2

+2x+2y+1=0

Foot of perpendicular from (−1,

2

3

) to y+1=0

0

h+1

=

1

k+

2

3

=−1

1

(3+1)

h=−1,k=−1

solution

Answered By

toppr

93 Views

How satisfied are you with the answer?

This will help us to improve better