Question

find the equation of the circle atC(-5,-1), ang tangent to the line x+y+10=0.​

Answer 1

Step-by-step explanation:

$r = \frac{ | - 5 - 1 + 10| }{ \sqrt{ {5}^{2} + {1}^{2} } } = \frac{4}{ \sqrt{26} } \\ \\ {(x + 5)}^{2} + {(y + 1)}^{2} = {r}^{2} \\ \\ {(x + 5)}^{2} + {(y + 1)}^{2} = ( { \frac{16}{ \sqrt{26} }) }^{2}$