Question

find the equation of the circle for which the points given
below are the end points
of a diameter
(1,2),(8,6)​

Answer 1

Equation of circle when end points of diameter are given is given by:

(x-x1)(x-x2) - (y-y1)(y-y2) = 0

Here, x1 = 1

x2 = 8

y1 = 2

y2 = 6

Thereby the equation becomes,

(x-1)(x-8) - (y-2)(y-6) = 0

=> x^2 - 9x + 8 - y^2 + 8y - 12 = 0

=> x^2 - y^2 - 9x + 8y - 4 = 0