Question

find the equation of the circle
(ii) whose centre is the point (2, 3) and which passes through the intersection of the lines
3x - 2y - 1 = 0 and 4x + y - 27 = 0.​

Answer 1

Answer:

x²+y²-4x-6y-12=0

Step-by-step explanation:

the lines 3x-2y-1=0 and 4x+y-27 intersect each other at (5,7)

the centre of the circle is at (2,3) and (5,7) lies in the circle

so radius is [(5-2)²+(7-3)²]^½=5 unit

so equation of the circle is given by

(x-2)²+(y-3)²=5²

or x²+y²-4x-6y-12=0