Question

find the equation of the circle passing (1,-2) and (4,-3) and whose center lines on the line 3x +4y=7​

Answer 1

Answer:

$let \: the \: centre \: of \: circle \: is \: (a \: and \: b) \\ \\ {(a - 1)}^{2} + {(b + 1)}^{2} = \red{ {(a - 4)}^{2} + {(b + 3)}^{2} } \\ \\3a - b = 10 \: ......(1) \\ \\ centre \: is \: lie \: on \: the \: line \: 3x + 4y = 7 \\ so \: it \: satisfied \: to \: this \: line \\ \\ 3a + 2b = 7.......(2) \\ \\ \: from \: (1) \: and \: (2) \: a = 3 \: and \: b = - 1 \: \\ \\ centre \: of \: the \: circle \: is \: (3 \: and - 1) \\ \\ so \: the \: equation \: of \: circle \: is \: \\ {x}^{2} + {y}^{2} - 6x + 2y + 5 = 0 \\ \\ \\ \\ \huge \red{ \boxed{\mathfrak{solution}}}$

Answer 2

Hey friend u can my friend