Question

find the equation of the circle passing throug the point 2,3 and -1,1 and whose centre is on the line x-3y-11=0​

Answer 1

here,

centre= x-3y=0

x= 3y(1)

Now,

(x-h)²+(y-k)²= r²

(2-h)²+(3-k)²= r² (2)

(-1-h)²+(1-k)²= r² (3)

equation 2= equation 3

4+h²-4h+9+k²-6k= 1+h²-(-2h) + 1+k²-2k

11-6h=4k

4k+6h=11