Question

Find the equation of the circle passing through (2,1), (5,5), (-6,7)?

Answer 1

Answer:

Answered Jan 6, 2018 · Upvoted by ... What is the equation of the circle passing through (-1, 5) and (-7, 5) and ... Putting x=2 and y=1.

3 votes

So you can see through diagram Centre of circle is (a,a) So it's equation is (x-a)^2+(y-a)^2=a^2 Putting x=2 and y=1 a^2–6a+5=0 a=1,5 x^2+y^2–2x-2y+1 ..

Answer 2

Answer:

Step-by-step explanation:

method  ( family of circles )

taking 2,1 and 5,5 as diametric end point

x-2*x-5 + y-1*y-5 = 0

and line joining 2,1 and 5,5

4x-3y=5

x-2*x-5 + y-1*y-5 + lamda(4x-3y-5) = 0

-6,7 satisfy above equation

-8*-11+(6*2)+lamda(-50) = 0

100+lamda(-50)=0

lamda=2

therefore equation of circle passing through points =

x-2*x-5+y-1*y-5 + 2(4x-3y-5) = 0

x^2-7x+10+y^2-6y+5+8x-6y-10=0

x^2+y^2+x-12y+5=0