Find the equation of the circle passing through
(-2, 14) and concentric with the circle
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Answer:
Given that the required circle
′
S
′
passes through (−2,14) and is concentric with the circle
S
1
≡x
2
+y
2
−6x−4y−12=0
∴ It's centre coincide with that of S
1
Now, centre of S
1
→
x
2
6x+9+y
2
−4y+4=12+4+9
⇒(x−3)
2
+(y−2)
2
=25
∴ centre of S=3,2
it's equation is (x−3)
2
+(y−2)
2
=a
2
it passes through (−2,14)
∴(−2−3)
2
+(14−2)
2
=a
2
a
2
=5
2
+12
2
=13
2
∴ equation of circle is
(x−3)
2
+(y−2)
2
=169
⇒x
2
+9−6x+y
2
+4−4y−169=0
⇒x
2
+y
2
−6x−4y−156=0
Step-by-step explanation:
hope it is helpful
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