Question

Find the equation of the circle passing through
(-2, 14) and concentric with the circle​

Answer 1

Answer:

Given that the required circle

′

S

′

passes through (−2,14) and is concentric with the circle

S

1

≡x

2

+y

2

−6x−4y−12=0

∴ It's centre coincide with that of S

1

Now, centre of S

1

→

x

2

6x+9+y

2

−4y+4=12+4+9

⇒(x−3)

2

+(y−2)

2

=25

∴ centre of S=3,2

it's equation is (x−3)

2

+(y−2)

2

=a

2

it passes through (−2,14)

∴(−2−3)

2

+(14−2)

2

=a

2

a

2

=5

2

+12

2

=13

2

∴ equation of circle is

(x−3)

2

+(y−2)

2

=169

⇒x

2

+9−6x+y

2

+4−4y−169=0

⇒x

2

+y

2

−6x−4y−156=0

Step-by-step explanation:

hope it is helpful