Question

Find the equation of the circle passing through (-2,3), (2, -1) and (4,0)​

Answer 1

Answer:

4x

Step-by-step explanation:

{4x}^{2} + y + 12 + {4y}^{2} + 144 + 48y equals \: to \: 145 \\ {4x}^{2} + {4y}^{2} + 12x + 48y + 8 \: equals \: to \: 0 \\ {x}^{2} + {y}^{2} + 3x + 2y + 2 \: equals \: to \: 0