Question

* Find the equation of the circle passing
through (-2, 3) (4, 5) and whose centre
lies on x-axis.​

Answer 1

Answer:

ANSWER

Given that the center lies on X axis. Let the coordinates of center of circle be (h,0)

The distance from center to points (−2,3) and (4,5) is equal

So we get (h+2)

2

+(0−3)

2

=(h−4)

2

+(0−5)

2

⇒12h=28

⇒h=

3

7

r

2

=(x−h)

2

+(y−k)

2

r

2

=(4−

3

7

)

2

+(5)

2

∴ The radius of circle is r=

25+

9

25

=

3

5

10

The equation of circle is (x−

3

7

)

2

+y

2

=

9

250