Find the equation of the circle passing through (3, −2), (1,2) and the point intersection of
the lines 2x +y − 3 = 0 x +y − 1 = 0. Also find the circumcentre.
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So, the vertices of the triangle lie on the circumference of the circle.
Let the coordinates of the circumcentre of the triangle be (x, y).
(x, y) will the equidistant from the vertices of the triangle.
Using distance formula, , it is obtained:
As (x, y) is equidistant from all the three vertices.
So, D1 = D2 = D3
D1 = D2
Adding equations (1) and (2):
∴ (3, –3) are the coordinates of the circumcentre of the triangle.
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