Question

find the equation of the circle passing through (- 7,1)and having centre (- 4, - 3)

Answer 1

passes(-7,1) equation is (x+4)^2 + (y+3)^2 = r^2
=3^2 + 4^2 = r^2
r = 5
(x+4)^2 + (y+3)^2 = 25

Answer 2

Step-by-step explanation:

(x-h)^2+(y-k)^2=r^2

h= -4;K= -3

(x+4)^2+ (y+3)^2=r^2

distance between the point and centre = radius

√(4+7)^2+ (-3 -1)^2

√3^2+-4^2

√9+16

√25

5

(x+4)^2+ (y+3)^2=5^2

x2+8x+16+y2+6y+9=25

x2+y^2+8x+6y=0