find the equation of the circle passing through origin and cutting off intercepts a and b from x axis and y axis
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we know that:
equation of circle:
(x-h)²+(y-k)²=r²
(x-a)²+(y-b)²=(√a²+b²)²
x²+a²-2ax+y²+b²-2by=a²+b²
x²+y²-2ax+-2by=0.
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equation of circle:
(x-h)²+(y-k)²=r²
(x-a)²+(y-b)²=(√a²+b²)²
x²+a²-2ax+y²+b²-2by=a²+b²
x²+y²-2ax+-2by=0.
please mark me brainliest
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