Question

find the equation of the circle passing through point (1,2)(2,0) and (-6,-6)​

Answer 1

Answer:

There are two ways

1 . Let equation be

${x}^{2} + {y}^{2} + 2gx + 2fy + c = 0$

satisfy the points and solve for variables .

2.

First find mid points of each side then write equation of any two perpendicular bisector . There intersection will give circumcentre and it's distance from any vertex is your radius.