Question

find the equation of the circle passing through the origin and having the centre at (-4,-3).​

Answer 1

Answer:

if a circle passing through origin,the general equation is x^2+y^2=r^2

r=√(-4)^2+(-3)^2=5

equation is:x^2+y^2-5=0

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Answer 2

Step-by-step explanation:

centre(-g,-f)= -4,-3.. c=0.

the general circle equation x^+y^+2gx+2fy+c=0..

substitute above equation in given formula

x^+y^+2(4)x+2(3)y+c=0

x^+y^+8x+6y=0

this is the required equation...