Question

Find the equation of the circle passing through the
points (1,2)(3.-4) and (5.-6).​

Answer 1

Step-by-step explanation:

Let point (1,2) be A , (3,−4) be B and (5,−6) be C

Let the mid point of AB be D=(2,−1) and the midpoint of BC be E=(4,−5)

• The equation of line passing through D and perpendicular to AB is x−3y=5
• The equation of line passing through E and perpendicular to BC is x−y=9

The center of circle is the point of intersection of above two lines which is equal to (11,2)

■ The radius of circle is 10

Therefore the equation of circle is (x−11)^2 + (y−2)^2 =100

Hope this will help you

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Answer 2

Answer:

("1,23.-45.-6.-7,8")

Step-by-step explanation:

you need to count by twos, in the... "maybe algebra?" "oh!" I don't know but all I know right now is "that you have to count by twos!"