Find the equation of the circle passing through the
points (1,2)(3.-4) and (5.-6).
Answers
Answered by
0
Step-by-step explanation:
Let point (1,2) be A , (3,−4) be B and (5,−6) be C
Let the mid point of AB be D=(2,−1) and the midpoint of BC be E=(4,−5)
- The equation of line passing through D and perpendicular to AB is x−3y=5
- The equation of line passing through E and perpendicular to BC is x−y=9
The center of circle is the point of intersection of above two lines which is equal to (11,2)
■ The radius of circle is 10
Therefore the equation of circle is (x−11)^2 + (y−2)^2 =100
Hope this will help you
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Answered by
0
Answer:
("1,23.-45.-6.-7,8")
Step-by-step explanation:
you need to count by twos, in the... "maybe algebra?" "oh!" I don't know but all I know right now is "that you have to count by twos!"
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