Question

Find the equation of the circle passing through the points (2,3) and (-1,1) and
whose centre is on the line x – 3y - 11 = 0 V​

Answer 1

Answer:

x-3y+7=0

Step-by-step explanation:

x-3y-11=0

-3y=-x+11

3y=x+11( as - sign is cancelled on both side)

y= x/3+11/3

as we know y=mx+c so m be 1/3

so putting in the formula (y-y1)=m(x-x1)

(y-3)=1/3(x-2)

3y-9=x-2

x-3y-2+9=0

x-3y+7=0