Question

Find the equation of the circle passing through the points (3,4) (3,2) (1,4)

Answer 1

Answer:

x^2+y^2-4x-6y+11 =0

Step-by-step explanation:

Let eqn. Of circle be x^2+y^2+2gx+2fy+c

Now satisfy all those three points in the eqn. U get 3 eqns in terms of g, f, c

6g+8f+c= - 25

6g+4f+c= - 13

2g+8f+c= - 17

g= - 2, f= - 3.,, "=11

Put the values in eqn