Question

Find the equation of the circle passing through the points (5, 7), (6, 6) and (2,-2).
Answer me fast !! please!!
​

Answer 1

Step-by-step explanation:

let O be the centre of the circle and O(x,y) then .

let the radius be OA=(5,7) ;OB=(6,6) ;OC=(2,-2).

THEREFORE.

OA=OB=OC(Radius of circle)

OA=OB

OA^2=OB^2

(x-5)^2+(y-7)^2=(x-6)^2+(y-6)^2

=>x^2-10x+25+y^2-14y+49=x^2-12x+36+y^2-12x+36

=>-10x+25-14y+49=-12x+36-12y+36

=>-10x+12x-14y+12y=36+36-49-25

=>2x-2y=72-74

=>2(x-y)=-2

=>x-y=-2/2

=>x-y=1