Question

Find the equation of the circle passing through the points P(1,1) , Q(2,-1) and R(3,2) .​

Answer 1

Step-by-step explanation:

ANSWER

Let C (h,K) be the centre and A,B be the given points, then 

CA2=CB2=r2=p2

Where p is perpendicular from  centre to the tangent 3x+y−3=0

CA2=CB2⇒h+k=5

CA2=p2⇒(h−1)2+(k−2)2

=(103h+k−3)

Now eliminate k and you wil find 

2h2−11h+12=10

Hence the circles are (x−h)2+(y−k)2=r2