Question

find the equation of the circle radius 5 and concentric of the circle x²+y²-6x+ 4y+12=0​

Answer 1

Step-by-step explanation:

The centre of required circle $\equiv (3,-2)$

radius =5

Equation of circle:

$(y + 2) ^{2} + (x - 3)^{2} = 25$

$\implies {x}^{2} + {y}^{2} - 6x + 4y - 12 = 0$