Question

find the equation of the circle that passes through the point (0,1) (0,-1) (1,1)​

Answer 1

Answer:

${x }^{2} + {y}^{2} = 1$

Step-by-step explanation:

$(x - 0)(x + 0) + (y - 1)(y + 1) = 0 \\ \\ {x}^{2} + {y}^{2} - 1 = 0 \\ \\ {x }^{2} + {y}^{2} = 1$