Question

Find the equation of the circle which has its
centre as intersection point of the lines x + y= 5; 2x – 4y = -8 and passes through the
origin.
(1) (x - 2)2 + (y - 3)2 = 13
(2) (x + 3)2 + (y + 2)2 = 13
(3) (x + 2)2 + (y + 3)12 = 13
(4) (x – 3)2 + (y - 2)2 = 13​

Answer 1

Answer:

1)(x-2)^2+(y-3)^2=13

Step-by-step explanation:

hope it helps