Find the equation of the circle which is concentric with the circle x^2+ y^2-12y-8x+15=0 & passing through the centre of the x^2 +y^2
abhi178:
hey friends please again look your question I think you missed x^2+y^2 = what
sorry .. mistakenly ...it is x^2+y^2-6y-4x+11=0.....
Answers
Answered by
1
first of all you find given circle center
i.e (4,6)
now let radius of unknown circle is r
hence equation of circle
(x-4)^2+(y-6)^2=r^2-------(1)
because this circle passing through
x^2+y^2-6x-4y+11=0 this circle center is (3,2)
now put (3,2) in (1) and find radius
and again write circle equation
i.e (4,6)
now let radius of unknown circle is r
hence equation of circle
(x-4)^2+(y-6)^2=r^2-------(1)
because this circle passing through
x^2+y^2-6x-4y+11=0 this circle center is (3,2)
now put (3,2) in (1) and find radius
and again write circle equation
I hope this is helpful
please mark as brainliest
wait I correct my answer
i got it thanks ......... how to mark brainliest???
now you look my answer
yah i did...it was really good of you
your tap my answer option come
and follow me for doubt
okay
Similar questions