Question

Find the equation of the circle which passes through (4, 1), (-4,-3) and (2,-5).​

Answer 1

Answer:

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Answer 2

Let the center be C( a, b ) and the radius r.

The three points are at the same distance r, from C. So,

r²=(a−4)2+(b−3)2=(a+2)2+(b+5)2=(a−5)2+(b−2)2, giving

3a+4b+1=0andb=−a. Solving,

a=1,b=−1andr=5. So, the equation of the circle is

(x−1)2+(y+1)2=25