find the equation of the circle which passes through the origin and cuts off intercepts 3 unit and 4 nit respectively find the equation of that diameter of the circle that passes through the origin
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Find the equation of the circle which
passes through the origin and cuts off
intercepts 3 and 4 from the positive
parts of the axes respectively. My Attempt, The circle cuts the axis of X at (3,0) and
the axis of Y at (0,4). Let r be the radius
of the circle. Since the circle passes
through the origin, r=√h2+k2 , Where, (h,k) are the co ordinates of the
centre of the circle.
passes through the origin and cuts off
intercepts 3 and 4 from the positive
parts of the axes respectively. My Attempt, The circle cuts the axis of X at (3,0) and
the axis of Y at (0,4). Let r be the radius
of the circle. Since the circle passes
through the origin, r=√h2+k2 , Where, (h,k) are the co ordinates of the
centre of the circle.
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