find the equation of the circle which passes through the origin and cuts off intercepts of 'a' , each from positive directions of the axes.
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Step-by-step explanation:
x^2 + y^2 + 2gx +2fy+c= 0 solve this for the three points and you will get your required equation of the circle. METHOD 2: You can use another method. Just see thecircle goes through the origin and at the origin x and y axis are perpendicular and you also know that semicircular angle is a right angle.
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