Math, asked by rohan585395, 8 months ago


Find the equation of the circle which passes through the points
(2, -2) and (3, 4) and whose centre lies on the line x+y=2x+y=2.​

Answers

Answered by itzJitesh
4

Step-by-step explanation:

Find the equation of the circle which passes through the points

(2, -2) and (3, 4) and whose centre lies on the line x+y=2x+y=2.

Answered by Anonymous
4

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r". This form of the equation is helpful, since you can easily find the center and the radius.

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