Question

find the equation of the circle which passes through the points (1,1) (2,-1) and (3,2)

Answer 1

It Is Lengthy Process Any Way I Will Explain How To Solve
First Of All ax^2+by^2+2gx+2fy+c=0 Is The General Equation Of The Circle Which Is Not Passing Through Origin And Then Substituting Each And Every Values And Then You Will Get Three Equations And Then Simplifying Then You Will Get The Values Of a, b, c, f And g Then Substitute In The General Equation Then You Will Get Required Circle Equation