Question

Find the equation of the circle which passes through the point (1, 4) and whose equation of two diameters are x – y = 1 and 2x + 3y = 7​

Answer 1

Step-by-step explanation:

Center is the meet of

x−y=1

2x+3y=7

3x−3y=3

5x=10

x=2

y=1

We have a center (2,1) and a point (1,4) so a squared radius

k=(2−1)2+(1−4)2=10

(x−2)2+(y−1)3=10