Question

Find the equation of the circle which passes through the point (1, 4) and whose equation of two diameters are x – y = 1 and 2x + 3y = 7

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Answer 1

Step-by-step explanation:

Since those lines are not parallel, and include diameter of the circle, they must intersect at the center of the circle. We can find that intersection by substituting one equation into the other:

x=y+1

2(y+1)+3y=7⟹5y=5⟹y=1

x=1+1=2

Thus, the center is at (2,1) .

Now, we need the radius (or radius squared, really.) That’s the distance between the center (2,1) and given point (1,4) :

(2−1)2+(1−4)2=r2⟹10=r2

Thus, our circle is given by:

(x−2)2+(y−1)2=10

Answer 2

Step-by-step explanation:

Two diameters are the lines,

x+y=4 ----- ( 1 )

x−y=2 ----- ( 2 )

So, first, we find the intersection point of diameters that is the center of the circle.

Adding equation ( 1 ) and ( 2 ) we get,

⇒ 2x=6

⇒ x=3

Substituting value of x in equation ( 1 ),

⇒ 3+y=4

⇒ y=1