Math, asked by simrankaur6, 11 months ago

Find the equation of the circle which passes through the origin and cuts orthogonally each of the circle,
x { }^{2}  + y {}^{2}  - 8x + 12 = 0
x {}^{2}  + y {}^{2}  - 4x - 6y - 3 = 0

Answers

Answered by velavan01
0

4 \sqrt[9 \sqrt[8 \sqrt[77 \sqrt[594 {4 \frac{y \frac{yyy \sqrt[44 \sqrt[9y \sqrt[ -  \div  -  \div  \times 806.9.9.9.. \times \frac{?}{?} ]{?} ]{?}  \times \frac{?}{?} ]{?} }{?} }{?} }^{?}  \times \frac{?}{?}  \times \frac{?}{?} ]{?}  \times \frac{?}{?}  \times \frac{?}{?} ]{?} ]{?} ]{?}  \times \frac{?}{?}  \times \frac{?}{?}
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