Math, asked by chinnaposamapenumaku, 4 months ago

Find the equation of the circle which touches the circle x2 + y - 4x + 6y - 12 = 0
(-1, 1) internally with a radius of 2.

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Answered by Anonymous

3

Answer:

Find the equation of the circle which touches the circle x2 + y - 4x + 6y - 12 = 0

(-1, 1) internally with a radius of 2.

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